I need the help big time. Answer this problem in its entirety. thank you 6. -15

Question

I need the help big time. Answer this problem in its entirety. thank you

6. -15 points My Notes Ask Your In the case of a uniform electric field and a flat surface, the electric flux is defined as the dot product of the electric field and the area, where the direction of the area is the normal to the area pointing out of a closed region, -E-A Consider a cube that measures 6.0 m on edge. The edges lie along the coordinate axes x, y, and z, with one corner at the origin, and the other corners having positive coordinates. A uniform and constant electric field points along the +z-axis with magnitude 4.5 N/C. Fig. 23-27 (a) What is the direction of the area vector on the top surface of the cube? G-Select- (b) What is the electric flux through the top surface? (c) What is the electric flux through the front surface? (d) The electric field is rotated through 30o toward the x axis. What now is the electric flux through the top surface? N m2/ (e) What now is the electric flux through the front surface? N m2/c Submit Answer Save Progress Practice Another Version

Explanation / Answer

a) along +z axis or along +k.

b) flux= EA cos 0= 4.5*6*6= 162 Nm^2/ C

c) flux= EA cos 90= 0 Nm^2/C

d) flux= EA cos 30= 6*6*4.5*cos30= 140.3 Nm^2/C

e) now angle between the area vector and electric field is (90-30)= 60

flux= EAcos 60= 6*6*4.5*cos 60= 81 Nm^2/C

comment in case any doubt

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