At the 0.75-m mark D | Question 2 What is the torque of a 34 N force that acts p

Question

At the 0.75-m mark D | Question 2 What is the torque of a 34 N force that acts perpendicularly at a point that is 2 m from the fixed por (pivot) of a long horizontal stick? Give your answer as whole number (integer). The Si unit of torque is N.m. D | Question 3 1 pts For the meter stick shown in the figure shown below, the force F1 is unknown and it acts at the 10- cm mark. Fi is balanced by another force, F2- 64 N that acts at the 70-cm mark What is the magnitude F1 in Newtons, about an axis through the point B? Please round your answer to one decimal place. 10 30 40 50 7080 90 n 4

Explanation / Answer

2...torque = force *distance

= 34*2

= 68 N-m

3..for balance

F1*(50-10) = F2* (70-50)

so F1 = 64*20/40

32 N

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