16) For each of the three balls in the previous problem, calculate the square-ro
ID: 777584 • Letter: 1
Question
16) For each of the three balls in the previous problem, calculate the square-root of the ratio of its final height after the bounce to its initial height before the bounce. [Enter your answers in the boxes below in the same order that the different types of balls are listed in the question.] Answer 1 of 3: Answer 2 of 3: Answer 3 of 3: 17) On board the international space station, a bouncy ball is thrown and collides head-on with another bouncy ball of three times the first one's mass. The collision is elastic. (a) What is the ratio of the final velocity of the lighter ball to its initial velocity? (b) What about the ratio of the heavier ball's final velocity to its the lighter ball's initial velocity? Use the first input box for your answer to (a) and the second for your answer to (b) Answer 1 of 2: Answer 2 of 2: 18) Which combination of statements is most accurate? [Enter your answer as a string of the letter options you believe are correct. For instance, if you think options A, D, and E are correct, then enter "ADE". NOTE: There are only 5 tries for this problem] A) The chemical energy stored in food is an example of source energy. B) Source energy can never be purely converted into mechanical energy. C) Macroscopic processes that change source energy don't always increase thermal energy as well. D) Mechanical energy can never be converted back into source energy E) None of the above Answer: 19) You push a 34 kg crate, accelerating from rest to a speed of 4 m/s. You use up 2000J of your energy. How energy efficient is this process? 20) How much thermal energy was generated by your efforts and the sliding friction acting on the crate? Answer:Explanation / Answer
(17 ) ans
According to the concept of the collision
V1={(m1-m2)u1/(m1+m2)}+{2m2u2/(m1+m2)}
V2={2m1u1/(m1+m2)}+{(m2-m1)u2/(m1+m2)}
Given that
mass m1=m
mass m2=2m
now we find the ratio of the finial and initial velocity of the each ball
lighter ball =>
V1={(m-3m)u/(m+3m)}+2*3mu/(m+3m)}
=(-2mu/m1+m2)+(6mu/4m)
=4mu/4m
V1=u
V1/u=1
heiver ball :-
V2=[(2*mu/(m+3m)]+[(3m-m)u/m+3m]
=2mu/4m+2mu/4m
=4mu/4m
V2/u=4m/4m=1
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(19) ans
Given that
mass m=34 kg
initial velocity u=0
finial velocity v=4 m/s
energy E=2000 j
now we find the efficient energy
basing on the concept of the work energy therom
E=1/2m(v^2-u^2)=1/2*34*4^2=272 J
now we find the amount of the thermal energy generated by efforts
heat energy Q=E-W=2000-272=1728 J
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