Chapter 30, Problem 029 In the figure, a metal rod is forced to move with consta

Question

Chapter 30, Problem 029 In the figure, a metal rod is forced to move with constant velocity along two parallel metal rails, connected with a strip of metal at one end. A magnetic field of magnitude B = 0.367 T points out of the page. (a) If the rails are separated by 36.4 cm and the speed of the rod is 60.0 cm/s, what is the magnitude of the emf generated in volts?(b) If the rod has a resistance of 22.0 2 and the rails and connector have negligible resistance, what is the current in amperes in the rod? (c) At what rate is energy being transferred to thermal energy? (a) Number (b) Number (c) Number Units Units Units

Explanation / Answer

a)

The magnitude of induced emf is determined by using the formula,

emf = B*l*v

Given :-

B = 0.367 T

l = 0.364 m

v = 60 cm/s = 0.60 m/s

emf = 0.367 T x 0.364 m x 0.60 m/s

emf = 0.080 V

b)

I = emf / R

I = 0.080 V / 22 ohm

I = 3.64 x 10^-3 A

c)

The rate at which the energy is being transferred is determined by using the formula,

P = emf x I

P = 0.080 V x 3.64 x 10^-3

P = 2.912 x 10^-4 W

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