Chapter 08, Problem 062 In the figure a block slides along a path that is withou

Question

Chapter 08, Problem 062 In the figure a block slides along a path that is without friction until the block reaches the section of length L = 0.75 m, which begins at height h 1.4 m, on a ramp of angle 30 In that section the coefficient of kinetic friction is 0.440 . The block passes through point A with a speed of 8.2 m/s. If the block can reach point B (where the friction ends), what is its speed there, and if it cannot, what is its greatest height above A? Number Unit the tolerance is +/-396 GO TUTORIAL By accessing this Question Assistance, you will learn while you earn points based on the Point Potential Policy set by your instructor Question Attempts: o of 5 used SAVE FORLE SUBMIT ANSWER

Explanation / Answer

We will use Work energy principle to solve this question.

Total energy at A = Total energy at B - Work done against friction

So, KE + PE at A = KE + PE at B - Work done

So, 0.5*m*8.2^2 + 0 = 0.5*m*v^2 + m*9.8*(h + L*sin(30 deg)) - 0.44*m*9.8*cos(30 deg)*L

So, 0.5*8.2^2 + 0 = 0.5*v^2 + 9.8*(1.4 + 0.75*sin(30 deg)) - 0.44*9.8*cos(30 deg)*0.45

So, v = 5.98 m/s <------ It reaches at point B with speed 5.98 m/s

Related Questions

Navigate

• Browse (All)
• Browse C
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.