The rate of effusion of an unknown gas was measured and found to be 11.5 mL/min.

Question

1. The rate of effusion of an unknown gas was measured and found to be 11.5 mL/min. Under identical conditions, the rate of effusion of pure oxygen (O2) gas is 13.5 mL/min. Based on this information, the identity of the unknown gas could be: N2 CO N2O C2H2 none of these

The rate of effusion of an unknown gas was measured and found to be 11.5 mL/min. Under identical conditions, the rate of effusion of pure oxygen (O2) gas is 13.5 mL/min. Based on this information, the identity of the unknown gas could be: N2 CO N2O C2H2 none of these The rate of effusion of an unknown gas was measured and found to be 11.5 mL/min. Under identical conditions, the rate of effusion of pure oxygen (O2) gas is 13.5 mL/min. Based on this information, the identity of the unknown gas could be: N2 CO N2O C2H2 none of these N2 CO N2O C2H2 none of these

Explanation / Answer

Rate effusion unknown gas / rate effusion O2
= sqrt( Molar mass O2 / molar mass unknown gas )

11.5 /13.5 = sqrt(32/x)

x =44

molar mass of unknown gas is =44
hence N2O =28+16 = 44

answer is N20

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