Two parts: as follows: 2 Cu(s) + CI2(aq) rightarrow 2 CuCI(s) Write balanced equ
ID: 799112 • Letter: T
Question
Two parts: as follows:
Explanation / Answer
a) reduction half cell 2Cu(s) ---> 2 Cu+(aq) + 2e-(aq)
oxidation half cell Cl2 (g) + 2e-(aq) -------> 2Cl-(aq)
b) E0 rxn = Eo( Cl2/2Cl-) -Eo( Cu+/Cu) = 1.3583 - 0.521 = 0.8373 V
dGo = -nFE = - 2 x 96485 x 0.8373 = - 161574 J = -161.574 KJ
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