OO Verizon LTE 12:14 PM webassign.net (a) How many moles of sodium iodide are ne

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OO Verizon LTE 12:14 PM webassign.net (a) How many moles of sodium iodide are needed to remove 2.4x10-5 mol O3? mol (b) How many grams of sodium iodide are needed to remove 0.400 mg of O3? Supporting Materials Periodic Table Hydrogen cyanide, HCN, is a poisonous gas. The lethal dose is approximately 300 mg HCN per kilogram of air when inhaled. (a) Calculate the amount of HCN that gives the lethal dose in a small laboratory room measuring 13 x 20. 9.1 ft. The density of air at 26°C is 0.00118 g/cm3. (b) If the HCN is formed by the reaction of NaCN with an acid such as H2SO4, what mass of NacN gives the lethal dose in the room? 2 NaCN(s) H2SO4(aa) Na2sos(aa) 2 HCN(g) (c) HCN forms when synthetic fibers containing Orlon or Acrilan burn. Acriland has an empirical formula of CH2CHCN, so HCN is 50.9% of the formula by mass. A rug measures 13 x 20, ft and contains 30 oz of Acriland fibers per square yard of carpet. If the rug burns, will a lethal dose of HCN be generated in the room? Assume that the yield of HCN from the fibers is 20% and that the carpet is 50% consumed. Yes No Supporting Materials Periodic Table Home My Assignments Extension Request

Explanation / Answer

Hydrogen cyanide is a poisonous gas. The lethal dose is approximately 300 mg HCN per kilogram of air when inhaled.

a. Calculate the amount of HCN that gives the lethal dose in a small laboratory room measuring 12 by 15 by 8.0 ft. The density of air at 26 degrees Celsius is 0.00118 g/cm3.

b. If the HCN is formed by reaction of NaCN with an acid such as H2SO4, what mass of NaCN gives the lethal dose in the room?
2NaCN(s) + H2SO4 --> Na2SO4 (aq) + 2HCN (g)

c. HCN forms when synthetic fibers containing Orion or Acrilan burn. Acrilan has an empirical formula of CH2CHCN, so HCN is 50.9% of the formula mass. A rug measures 12 by 15 ft. and contains 30 oz of Acrilan fibers per square yard of carpet. If the rug burns, will a lethal dose of HCN be generated in the room? Assume that the yield of HCN from the fibers is 20% and that carpet is 50% consumed.

QUESTION a)
The room you describe contains a volume like

12 X 15 X 8 = 1440 cubic-feet = 47 cubic-meters

which contains air stading at condition assuring a Ponderal Density like

1.18 g / Liter = 1180 g / cubic-meters

Then, the air mass present in the room is

1180 * 47 = 55700 grams of gas

then the required amount to reach Lethal Dose is

55700 * 300E-6 = 16.7 grams of HCN

QUESTION b)
Since the HCN comes from sulphuric bath, you look for the mass amount of NaCN required to leaves up HCN. Then the reaction follows

2 NaCN(s) + H2SO4(aq) --> Na2SO4(aq) + 2 HCN(g)

stating a STOICHIOMETRIC RATIO LIKE

NaCN : HCN = 2 : 2

assuring that ONE MOLE OF Hydrogen Cyanide COMES FROM ONE MOLE OF Sodium Cyanide. Then, mathematically

(16.7 / (1 + 12 + 14)) = (x / (23 + 12 + 14))

the mass amount you need is

x = 16.7 * 49 / 27 = 30.3 grams of NaCN

QUESTION N.3)
Acrylan is a synthetic clothes made by ACRYLONITRILE (e.g. CH2CH=CN) bearing HCN in feature of 50.9%.
The rug burned the 50% of its whole surface, e.g. 50% of the whole surface 12 X 15 square-feet

0.50 X 12 X 15 = 90 square-feets = 9.2 square-meters

This area has a weight corresponding to

30 * 9.2 / (0.914)^2 = 330 oz = 9340 grams of rug

This mass leaven off a corresponding amount of HCN by 20% of theoretical yield expressed in 50.9%

20% * 50.9% * 9340 = 950 grams of HCN

Yes, IT OVERTHROWS THE LETHAL DOSE!

I hope this helps you.

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