When dissolved in water fructose and glucose exist in equilibrium. A chemist pre

Question

When dissolved in water fructose and glucose exist in equilibrium.
A chemist prepared a .244M solution of fructose. When equilibrium is reached its concentration had decreased to .113M. Calculate Kc for this reaction. When dissolved in water fructose and glucose exist in equilibrium.
A chemist prepared a .244M solution of fructose. When equilibrium is reached its concentration had decreased to .113M. Calculate Kc for this reaction.
A chemist prepared a .244M solution of fructose. When equilibrium is reached its concentration had decreased to .113M. Calculate Kc for this reaction.

Explanation / Answer

Fructose + H2O <=> 2 Glucose
At equilibrium: [Fruc]= 0.113 M
[Gluc]= 2* ( 0.244-0.113)= 0.262 M
Kc= [Gluc]

Related Questions

Navigate

• Browse (All)
• Browse W
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.