Water ionizes by the equation H2O(l)?H+(aq)+OH?(aq) The extent of the reaction i
ID: 811830 • Letter: W
Question
Water ionizes by the equation
H2O(l)?H+(aq)+OH?(aq)
The extent of the reaction is small in pure water and dilute aqueous solutions. This reaction creates the following relationship between [H+] and [OH?]:
Kw=[H+][OH?]
Keep in mind that, like all equilibrium constants, the value of Kw changes with temperature.
1) What is the H+ concentration for an aqueous solution with pOH = 4.18 at 25 ?C?
2) Arrange the following aqueous solutions, all at 25 ?C, in order of decreasing acidity.
0.0023M HCL, 0.0018M KOH, ph=5.45, pOH=8.55
3) At a certain temperature, the pH of a neutral solution is 7.61. What is the value of Kw at that temperature?
Explanation / Answer
1) 1.51 x10^-10
2) 0.0023M HCl > ph=5.45= pOH=8.55>0.0018M KOH (ph=5.45 and pOH=8.55 same acidic strength)
3) Kw= 6.0025 x 10^-16
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