Analyze and solve this partially completed galvanic cell puzzle. There are 4 ele
ID: 828451 • Letter: A
Question
Analyze and solve this partially completed galvanic cell puzzle. There are 4 electrodes each identified by a letter of the alphabet, A through D. The values in the partially completed grid are measured cell potentials for a cell consisting of electrode #1 and electrode #2. You may assume that each galvanic cell was properly constructed with the appropriate metals and solutions and that all the measured values in the grid are accurate.
electrode #1 ?
C
B
D
A
electrode #2?
Ecell(volts)
Ecell(volts)
Ecell(volts)
Ecell(volts)
C
0
0.91
0.62
0.26
B
0.91
0
1.53
D
0.62
1.53
0
0.36
0 volts
0.10 volts
0.26 volts
0.36 volts
0.55 volts
0.62 volts
0.65 volts
0.88 volts
0.98 volts
1.17 volts
1.27 volts
1.79 volts
1.89 volts
electrode #1 ?
C
B
D
A
electrode #2?
Ecell(volts)
Ecell(volts)
Ecell(volts)
Ecell(volts)
C
0
0.91
0.62
0.26
B
0.91
0
1.53
D
0.62
1.53
0
0.36
Explanation / Answer
Good question:
A-C = 0.26
D-A = 0.36
D-B = 1.53
D-C = 0.62
After trying various combination, below sequence logically fit
C-B = 1.53-0.62 = 0.91
A-C = 0.26
D-A = 0.36
D-B = 1.53 So D>A; D>B ; A>C; C>B D>A>C>B
I need to find B-A = 1.53-0.36 = 1.17 V
Cheers
Related Questions
drjack9650@gmail.com
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.