What is the molarity of zinc chloride that forms when 25 g of zinc completely re

Question

What is the molarity of zinc chloride that forms when 25 g of zinc completely reacts with copper (II) chloride to the following reaction? Assume a final solution volume of 275mL.
Zn(s) + CuCl2(aq) yields ZnCl2(aq) + Cu(s)
Which compound in the reaction shown above is acting as the reducing agent? Explain your answer. What is the molarity of zinc chloride that forms when 25 g of zinc completely reacts with copper (II) chloride to the following reaction? Assume a final solution volume of 275mL.
Zn(s) + CuCl2(aq) yields ZnCl2(aq) + Cu(s)
Which compound in the reaction shown above is acting as the reducing agent? Explain your answer.
Zn(s) + CuCl2(aq) yields ZnCl2(aq) + Cu(s)
Which compound in the reaction shown above is acting as the reducing agent? Explain your answer.

Explanation / Answer

Atomic mass of zinc = 65

No of moles in 25 gm = 25/65 = 0.38 moles

1 mole of Zn gives 1 mole of ZnCl2

275 mL = 0.38 moles

1 L = 0.38*1000/275 = 1.38 is the molarity of the ZnCl2 in the solution.

Zinc is the reducing agent as it loses electron and gets oxidized.

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