Find standard enthalpies of reaction in kilojoules for the following process Fe2

Question

Find standard enthalpies of reaction in kilojoules for the following process
Fe2O3(s)+3CO(g)-->2Fe(s)+3CO2(g)
In the preceeding reaction, _____________ is in elemental form and has a standard enthalphy of ______________. This reaction is a ___________ reaction. The standard enthalphy for the reaction is ____________kJ(3 significant figures) Find standard enthalpies of reaction in kilojoules for the following process
Fe2O3(s)+3CO(g)-->2Fe(s)+3CO2(g)
In the preceeding reaction, _____________ is in elemental form and has a standard enthalphy of ______________. This reaction is a ___________ reaction. The standard enthalphy for the reaction is ____________kJ(3 significant figures)
Fe2O3(s)+3CO(g)-->2Fe(s)+3CO2(g)
In the preceeding reaction, _____________ is in elemental form and has a standard enthalphy of ______________. This reaction is a ___________ reaction. The standard enthalphy for the reaction is ____________kJ(3 significant figures)

Explanation / Answer

DeltaHo(reaction) = sum{Delta Hof(products) - sum{Delta Hof(reactants)

Remember to multiply by the coefficient when there is more than one molecule or formula unit.

use the following reactions and given delta h's:
2Fe(s)+ 3/2O2(g)->Fe2O3(s), delta h=-824.2 kj
CO(g)+1/2O2(g)->CO2(g), delta h=-282.7

Flip the top equation round and change the delta sign [ So that we can cancel the O2 after the next step]
Fe2O3(s) -> 2Fe(s)+ 3/2O2(g) d.h = 824.2 kj

Multiply the bottom equation so that the O2 has the same number of moles as the top equation. (remember to multiply the delta h as well!)

[CO(g)+1/2O2(g)->CO2(g), delta h=-282.7 ] * 3
3CO(g) + 3/2 O2 -> 3CO2(g) d.h. =-848.1 kj

Line the 2 equations up
3CO(g) + 3/2 O2 -> 3CO2(g) d.h. =-848.1 kj
Fe2O3(s) -> 2Fe(s)+ 3/2O2(g) d.h = 824.2 kj

As you can see the 3/2 O2's cancel (because they're on opposite sides).
Leaving
3CO(g) -> 3CO2(g) d.h. =-848.1 kj
Fe2O3(s) -> 2Fe(s)+ d.h = 824.2 kj

Now add the 2 delta h's
-848.1 + 824.2
= -23.9 kj mol-1

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