Chemistry Please Help 1. At high temperatures, sulfur combines with iron to form

Question

Chemistry Please Help

1. At high temperatures, sulfur combines with iron to form the brown black iron (II) sulfide:

Fe(s) + S(l) -> FeS(s)

In one experiment, 7.62 grams of Fe are allowed to react iwth 8.67 grams of S.

a. What is the limiting reagant, and what is the reactant in excess?

b. Calculate the mass of FeS formed.

2. Arcylonitrile, C3H3N, is the starting material for the production of a kind of synthetic fiber acrylics, and can be made from propylene, C3H6, by reaction with nitric oxide, NO, as follows:

4 C3H6 (g) + 6 NO (g) -> 4 C3H3N (s) + 6 H2O (l) + N2 (g)

What mass of C3H3N can be made when 21.6 grams of C3H6 react with 21.6 g of nitric oxide?

3. Calculate % yield for the rxn: P4 (s) + 6 Cl2 (g) -> 4 PCl3 (l) if 75.0 grams of phosphorus reacts with excess chlorine gas to produce 111.0 g of phosphorus trichloride.

4. Consider the rxn: MnO2 + 4HCl -> MnCl2 + Cl2 + 2H2O

If 0.45 moles of MnO2 can react with 48.2 g of HCl, how many grams of Cl2 could be produced?

5. Calculate the percent (%) yield for an experiment in which 5.50g of SOCl2 was obtained in a reaction of 5.80 grams of SO2 with excess PCl5. Use the following equation:

SO2 (l) + PCl5 (l) -> SOCl2 (l) + POCl3 (l)

6. When iron (II) hydroxide is mixed with phosphoric acid, iron (II) phosphate precipitate results.

a. Balance the following equation: Fe(OH)2 (aq) + H3PO4 (aq) -> Fe3(PO4)2 (s) + H2O (l)

b. If 3.20 grams of Fe(OH)2 is treated with 2.50 g of phosphoric acid, what is the limiting reagantand what is the reactant in excess?

c. How many grams of Fe3(PO4)2 percipitate can be formed?

d. If 3.99 g of Fe3(PO4)2 is actually obtained, what is the percent yield?

Explanation / Answer

1) a) Fe is the limiting reagent, S is in excess

b) 12.2g FeS formed

2) 25.5 g C3H3N

3) % yield = 33.3%

4) 23.4 g Cl2

5) 51.0%

6)

a) 3 Fe(OH)2 (aq) + 2 H3PO4 (aq) ? Fe3(PO4)2 (s) + 6 H2O(l)

b) Fe(OH)2=limiting reagent, H3PO4 in excess

c) 4.24 g Fe3(PO4)2 (s)

d) 94.0%

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