If a total volume of 60 mL of 0.10 M NaOH is added to 40 mL of 0.10 M carbonic a

Question

If a total volume of 60 mL of 0.10 M NaOH is added to 40 mL of 0.10 M carbonic acid solution, the pH of the resulting solution will be? Please show work

For Questions 14 and 15, consider the diprotic acid carbonic acid H2CO3 in aqueous solution: H2CO3 + H2O rightleftharpoons HCO3- + H3O+ Ka1 = 4.3 X 10^-7 PKa1 = 6.37 HCO3- + H2O rightleftharpoons CO3 2- +H3O+ Ka2 = 4.8 x 10^-11 PKa2= 10.32 Acid solution, the resulting solution If a total volume of 60 mL of 0.10 M NaOH is added to 40 mL of 0.10 M carbonic acid solution, the pH of the resulting solution will be? Please show work

Explanation / Answer

NaOH completely dissociated as

NaOH---->Na+ +OH-

carbonic acid partialy dissociated (weak acid)

H2CO3------->H+ +HCO3-

pH= 14+log (CaCbKw/Ca+ Cb xKa)1/2

Ca= conc. of acid

Cb= conc. of base

Kw=dissociation constant for water

Ka=for base

after equvalence point solution contains two bases.conjugate base 0f the acid &strong base NaOH

pH=14+logCbVb-CaVa/Va+Vb=14+log0.1x60-0.1x40/60+40

=14+log6-4/100

=14+log 0.2

pH=15.1698

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