Consider the reaction between aluminum sulfate and barium chloride shown. Which

Question

Consider the reaction between aluminum sulfate and barium chloride shown. Which of the statements is FALSE?

Al2(SO4)3 + 3 BaCl2 ? 3 BaSO4 + 2 AlCl3

the fact that the number of each type of atom on each side is equal is related to the Law of Conservation of Mass.

6 "molecules" of barium chloride will make 6 "molecules" of barium sulfate

aluminum chloride is a product of the reaction

this is neither a synthesis nor a decomposition reaction

there will be 3/2 times as many aluminum chloride molecules made as there are molecules of barium chloride used.

the fact that the number of each type of atom on each side is equal is related to the Law of Conservation of Mass.

6 "molecules" of barium chloride will make 6 "molecules" of barium sulfate

aluminum chloride is a product of the reaction

this is neither a synthesis nor a decomposition reaction

there will be 3/2 times as many aluminum chloride molecules made as there are molecules of barium chloride used.

Explanation / Answer

option E is wrong because correct statement is there will be 2/3 times as many aluminuium chloride molecules made as there are molecules of barium chloride used. because for 3 moles of  barium chloride we get 2 moles of aluminuium chloride

3 moles of BaCl2 --------> 2 moles of AlCl3

1 mole of BaCl2 ----------> 2/3  moles of AlCl3

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