Consider the reaction between NO and Cl2 to form NOCl: 2NO( g )+Cl2( g )2NOCl( g

Question

Consider the reaction between NO and Cl2 to form NOCl:
2NO(g)+Cl2(g)2NOCl(g)
A reaction mixture at a certain temperature initially contains only [NO]= 0.62 M and [Cl2]= 0.53. After the reaction comes to equilibrium, the concentration of NOCl is 0.30 M .

Part A

Find the value of the equilibrium constant (Kc) at this temperature.

Express your answer using two significant figures.

Consider the reaction between NO and Cl2 to form NOCl:
2NO(g)+Cl2(g)2NOCl(g)
A reaction mixture at a certain temperature initially contains only [NO]= 0.62 M and [Cl2]= 0.53. After the reaction comes to equilibrium, the concentration of NOCl is 0.30 M .

Part A

Find the value of the equilibrium constant (Kc) at this temperature.

Express your answer using two significant figures.

Explanation / Answer

KC = NOCl2^2 /(NO^2)(Cl2)

[NO] = 0.62-2x

[Cl2] = 0.53-x

[NOCl] = 0 +2x

in equilibirum

In equiibriu [NOCl] = 0.3

x = 0.3/2 = 0.15

[NO] = 0.62-2x = 0.62-2*0.15 = 0.32

[Cl2] = 0.53-x = 0.52-0.15 = 0.37

then

KC = NOCl2^2 /(NO^2)(Cl2) = (0.3^2)/((0.32^2)(0.37)) = 2.3754

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