A) IO 3 ? is the reducing agent and the oxidized compound. C 2 O 4 2? is the oxi

Question

A) IO3? is the reducing agent and the oxidized compound. C2O42? is the oxidizing agent and the reduced compound. B) IO3? is the oxidizing agent and the reduced compound.
C2O42? is the reducing agent and the oxidized compound. C) C2O42? is the reducing agent and the reduced compound. IO3? is the oxidizing agent and the oxidized compound. D) H?+ is the reducing agent and the oxidized compound. H2O is the oxidizing agent and the reduced compound. Look at the reaction between oxalate and lodate ions. 5C2O2-4 (aq) + 2IO-3(aq) + 12H+ (aq) rightarrow 10CO2(g) + I2(aq) + 6H2O(l) Which of the following correctly identifies the oxidizing agent, the reducing agent, the oxidized compound, and the reduced compound?

Explanation / Answer

In the above case, the oxidation state of C changes from +3 for oxalate to +4 for CO2, thus it is getting oxidized, and is a reducing agent. On the other hand, oxidation state of Iodine changes from +5 for IO3- to 0 for I2 and is thus getting reduced and is an oxidizing agent.

Therefore, the correct answer will be,

B) IO3- is the oxidizing agent and the reduced compound, C2O42- is the reducing agent and the oxidized compound.

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