I did the equation correctly but I keep getting the Keq wrong. equilibria and ca

Question

I did the equation correctly but I keep getting the Keq wrong.

equilibria and caSpecies pKa Species pK Complete the equations for the following equilibria and calculate Keq where the Keq expression includes [H2O]. Be sure to enter Keq in proper scientific notation. NH3 35 H20 15.74 NH 9.251.74 NH4 9.25H (a) ammonia (acting as a base) reacts with water (acting as an acid) Number Ke1.78 x 102 (b) ammonia (acting as an acid) reacts with water (acting as a base) Number NH3 + H2O Keq3.11x 10 Which of these reactions is more important (i.e., prevalent) in an aqueous solution of ammonia? O reaction (a) O reaction (b)

Explanation / Answer

a) Keq = [NH4+][OH-]/[NH4OH]

for NH4+

pKa = 9.25

Ka = 5.6234x10-10

KaKb = Kw

Kw = 1x10-14

Kb = 1.78x10-5

  Keq = [NH2-][H+]/[NH3]

For NH3:

pKa = 35

  Ka= 1x10-35

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