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Checking answers and in need of some answers. 1. 142 55 Cs 3. k = 0.0594 / day 4

ID: 878353 • Letter: C

Question

Checking answers and in need of some answers.

1. 14255 Cs
3. k = 0.0594 / day
4. 9.97 * 10-7 / sec
6. KC = 0.0201

1. When U absorbs a neutron, fission occurs. One possible fission pathway is as follows: 37 What is the missing nuclide? The half-life of the radioactive nuclide "As is 9.0 min. of "As? 2. The molar mass of"As is 78.921 g/mol. What is the activity of a 9.8-ug sample (1 Ci = 3700x1010 disintegrations/s) 3. A sample of a radioactive isotope is found to have lost 39.9% of its original activity after 8.57 days. What is the decay constant of this isotope? Iodine-131 decays by beta emission with a half-life of 8.04 days. What is the decay constant for iodine-131? 4. 5. PCI3(g) + Cl2(g), Kc = 4.0 at 228°C. If pure PC15 is placed in a For the equilibrium PCIs(g) 1.00-L container and allowed to come to equilibrium, and the equilibrium concentration of PCls(g) is 0.26 M, what is the equilibrium concentration of PCl3? In an experiment, 0.4 M HI was mixed in a container, and the reaction establishes equilibrium. If at equilibrium the concentration of I2 is 0.0442 M. What is the Kc for the reaction? 6. 2HIg)I2(g) + H2(g)

Explanation / Answer

1.

92 U 235 + 0 n 1 ---à 3 0 n 1 + 37 Rb 89 +

To get the missing nuclide add atomic number and mass numbers of both sides and compare:

92 U 235 + 0 n 1:

Atomic number: 92+0= 92

Mass number: 235 +1= 236

3 0 n 1 + 37 Rb 89:

Atomic number: 37+0= 37

Mass number: (3*1) +89= 92

Now compare atomic number : 92-37 = 55

Atomic mass :236 – 92 = 144

Therefore the missing nuclei has atomic number 55 and mass 144 means Cs

Thus the reaction becomes:

92 U 235 + 0 n 1 ---à 3 0 n 1 + 37 Rb 89 + 55Cs 144

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