The equilibrium constant, K, of a certain first If you were going to graphically

Question

The equilibrium constant, K, of a certain first If you were going to graphically determine the enthalpy, order reaction was measured at two AH, for this reaction, what points would you plot? temperatues, T. The data is shown in this table. Number Number To avoid rounding errors, use three point 1: T (K) K significant figures in 5 3.84 275 the X values and four 625 6.60 significant figures in Number Number the y values. D D point 2 Determine the rise, run, and slope of the line formed by these points. rise slope Number Number What is the standard enthalpy of this reaction? Number J mol AH

Explanation / Answer

On x-axis:

Point 1 : 1/275 = 0.00363                        point 2: 1/625 = 0.0016

On y-axis

Point 1 : ln(3.84) = 1.345             point 2: ln(6.6 ) = 1.887

Rise y2 – y1
1.887 – (1.345) = 0.542
Run x2 –x1
0.0016 – 0.00363 = –0.00203

Slope = rise / run
0.542 / –0.00203 = –266.995

enthalpy of reaction

ln(K2/K1) = deltaH/R (1/T1 – 1/T2)

0.542= Delta H/8.314 (0.00203)
enthalpy = (0.542 x 8.314) / 0.00203 = 2219.79 J/mol

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