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1. Is the equivalence point of a weak acid-strong base titration acidic, neutral

ID: 888107 • Letter: 1

Question

1. Is the equivalence point of a weak acid-strong base titration acidic, neutral, or basic?

2. How is pKa determined from a weak acid-strong base titration?

3. A 0.6385 g sample of KHP is titrated to endpoint with 33.46 mL of NaOH. What is the NaOH concentration?

4. An unknown sample with a mass of 1.0 g requires 11.5 mL of titrant. What mass of unknown should be used for an analytical titration, with an approximate equivalent volume of 35 mL?

5. How is an endpoint found from a 2nd Derivate Potentiometric Titration plot?

pleeeease help me ASAP

Explanation / Answer

1)

the equivalence point of a weak acid strong base titration will be basic


2)

now

in the weak acid strong base titration

first find the equivalence point

then

the pKa is equal to the pH at half equal equivalence point


3)

at end point

moles of acid = moles of base

so

moles of KHP = moles of NaOH


now

moles = mass /molar mass

so

moles of KHP = 0.6385 / 204

moles of KHP = 3.13 x 10-3

so

moles of NaOH = 3.13 x 10-3


now


given

volume = 33.46 x 10-3 L

now

conc = moles / volume (L)

so

conc of NaOH = 3.13 x 10-3 / 33.46 x 10-3

conc of NaOH = 0.093 M


4)

in this case

mass of uknown = 1 x 35 / 11.5

mass of unknown = 3.04

so

3.04 g of unknown is required


5)

find the second derivative of the curve and equate it to zero