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A mouthwash bottle contains 20.5% alcohol by volume. If the bottle of mouthwash

ID: 893256 • Letter: A

Question

A mouthwash bottle contains 20.5% alcohol by volume. If the bottle of mouthwash contains 375mL, what is the volume in mililiters of the alcohol?

A patient needs 250g of glucose in the next 12 hours. How many liters of a 10% (m/v) glucose solution must be given?

Calculate the amount of solution (g or mL) that contains each of the following amounts of solute

1) 3.2g of LiNO3 from a 20%(m/m) LiNO3 solution

2) 33.0g of KOH from a 10.0%(m/m) KOH solution

3) 2.4mL of formic acid from a 8.0% (v/v) formic acid solution

Explanation / Answer

Part a) Volume of alcohol = (375 mL)(20.5/100) = 76.9 mL alcohol

Part b) 250 g = 10%, therefore, total volume of solution = 100*250/10 = 2500 mL = 2.5 L glucose solution should be given.

Part c)

1) Total mass of solution = 3.2 g*100 /20 = 16 g

2) Total mass of KOH solution = 33 g*100 /10 = 330 g

3) Total volume of the solution = 2.4*100/8 = 30 mL

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