A student collected the following data while using the procedure described in th

Question

A student collected the following data while using the procedure described in this module: 27.13 mL of 1.00 x 10^-2M EDTA soltuion was required to reach the ErioT end point for titration of 25.00 mL of the sample water.

After boiling and filtering 100.00 mL of the water, the student diluted the filtrate to 100.0 mL with distilled water. To titrate 25.00 mL of the diluted filtrate, 26.40 mL of 2.00 x 10^-1 M EDTA solution was required.

The studetn precipitated the Ca^2 ion as CaC2O4 from 75.00 mL of the water sample and removed the precipitate by filtration. The student then adjusted the water sample volume to 100.0 mL. To titrate 25.00 mL of the diluted filtrate, 7.43 of 1.00 x 10^-2 M EDTA solution was required.

a) calculate the number of millimoles of Ca^2+ and Mg^2+ ions present in the titrates sample.

b) calculate the total water hardness, expressed in ppm of equivalent CaCO3.

c) calculate the permanent water hardness in terms of Ca^2+ and Mg^2+ ions.

d) express the permanent water hardness in terms of ppm of equivalent CaCO3.

e) calculate the temporary water hardness in terms of ppm equivalent CaCO3.

f) calculate the number of milimoles of Mg^2+ ions per liter of the water.

g) Express the water hardness due to Mg^2+ ions in terms of ppm equivalent to CaCO3.

h) Express the water hardness due to Ca^2+ ions in terms of ppm equivalent CaCO3

Explanation / Answer

I can only answer a question because they are too many, if you want to solve all, you can upload in parts, do not show the precipitate with Mg so only calcium estimated by him.
C1 / C2 = V1 / V2
C2 = C1V2 / V1
C2 = 0.0743 * 0.025 / 0.075

C2=0.0247M Ca^2=24.76mM Ca^2

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