Chemical Engineering question Could you please solve the question? I exactly cop

Question

Chemical Engineering question

Could you please solve the question? I exactly copied the problem

Consider a 100 mol mixture that is 69.0% methane (CH4) and 31.0% ethane (C2Hs), To this mixture is added 25.0% excess air. Of the methane present, 90.50% reacts, 88.70% of which forms carbon dioxide (CO2), and the balance forms carbon monoxide (CO). Of the ethane present, 85.8% reacts, 88.70% of which forms carbon dioxide, and the balance forms carbon monoxide What is the theoretical amount of oxygen required for the fuel mixture? Number mol O What amount of air is added to the fuel mixture? Number mol air How many moles of methane are present in the product gas? Number mol CH

Explanation / Answer

I have a little doubt about this, however, I'll try to answer at least the first 4 sub parts of the question:

1) For the theorical oxygen of the mixture:

Write the reaction for both of methane and ethane with oxygen, and balance both of them:

CH4 + 2O2 -----------> CO2 + 2H2O

2C2H6 + 7O2 ----------> 4CO2 + 6H2O

Now If carefully look to both equations, the "theorical" amount of oxigen you need is 2 and 7, so the total should be 9 moles of O2.

Now, if we actually take the amount of CH4 and C2H6 in the mixture that are 69 and 31, the moles of theorical oxygen needed would be:

CH4: 69 x 2 = 138 moles

C2H6: 31x7 / 2 = 108.5 moles

The total would be 246.5 moles of Oxygen.

2) the amount of air.

If the excess added is 25%, we can assume that it's a 25% of the 100 mol base of the mixture, so The amount of air would be 25 mol: 100 x 0.25 = 25 moles of air.

3) Amount of CH4

It says that 69% of the 100 mol belongs to CH4 so: 100 x 0.69 = 69 mol of methane.

then, the 90.5% reacts: 69 x 90.5/100 = 62.445 moles reacted

so, the 9.5% didn't react, so in the product gas should be left:

69 - 62.445 = 6.555 moles of CH4

4) For ethane we do exactly the same thing as before:

31 moles x 85.8/100 = 26.598 moles reacted.

31 - 26.598 = 4.402 moles left of Ethane

For the rest of the question, I have some doubts in one procedure and I want to read and study that part a little longer, so, post the rest of the part of this question in another post meanwhile if you need this asap. If you don't, I'll check my books and then edit the question. Tell me if there's something wrong or anything else that you need.

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