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Chem 112 Use the References to access Important values If needed for this questi

ID: 897093 • Letter: C

Question

Chem 112 Use the References to access Important values If needed for this question. Bromine is one of the few elements that b a liquid at room temperature. It vaporizes easily and has a beautiful red color In both the liquid and gaseous states. Bromine reacts readily with hydrogen gas to make hydrogen bromide. One way to represent this equilibrium is: H_2(g) + Br_2(g) 2HBr(g) We could also write this reaction three other ways, listed below. The equilibrium constants for all of the reactions are related. Write the equilibrium constant for each new reaction in terms of K, the equilibrium constant for the reaction above.

Explanation / Answer

Given reaction is

H2 + Br2 --------> 2HBr

1)

For the reaction 2HBr -------> H2 + Br2

K1 = 1 / K (since the reaction is reversed)

2)

For the reaction (1/2) H2 + (1/2)/ Br2 -----> HBr

K2 = (K) ^(1/2)

3)

For the reaction HBr -------> (1/2) H2 + (1/2) Br2

K3 = (K1) ^(1/2) = (1 / K) ^ (1/2)

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