Chem 112 1. You know that the weak acids exists in aqueous solutions in equilibr

Question

Chem 112 1. You know that the weak acids exists in aqueous solutions in equilibrium with their dissociated ions. Write the equilibrium expression as a function of the K of a weak acid. 2. If 1 /2 of the weak acid were neutralized into salt, how would the concentration of the weak acid compare to the concentration of the salt? This is called the 1/2 neutralization point.) 3. If a sample is at the 1/2 neutralization point. what species are equivalent and can be cancelled from the Ka equation? Ka =

Explanation / Answer

1. Weak acid dissociates as,

HA <==> H+ + A-

So the equilibrium expression becomes,

Ka = [H+][A-]/[HA]

2. At half neutralization point,

concentration of acid = concentration of salt in solution

3. If the solution is at half neutralization point we can cancel the [A-] and [HA] from top and bottom

So we get,

Ka = [H+]

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