Chemistry. Can someone help me with number 6 with a step by step process? Please

Question

Chemistry. Can someone help me with number 6 with a step by step process? Please ag) Bart vit the e E(aqF(aq) B(aq) with the equilibrium constant -K d) What is the equilib hat is the equilibrium constant of A(a)+ E()D(aq)+ F(aq)? 4-The reaction of forming ammonía from hydrogen and nitrogen is at equiliborium in a close container. What would be the effect of increasing the volume of the container? Explain your answer in terms of thermodynamics. 5 Ka of acetic acid 1.8x105 What is the acetate ion concentration in a solution at equilibrium in which the concentration of acetic acid is 0.10 M and that of H3O* is 1.0X10- M? 6- 6.0 moles of hydrogen and 4.0 mole of nitrogen react to produce ammonia in a 10.0L flask. At equilibrium there is 1.0 mole of hydrogen remaining. What is the value of K? N OLE.IM

Explanation / Answer

Given :

Moles of H2 = 6.0

Moles of N2 = 4.0

Lets show the reaction

            N2 (g) + 3 H2 (g)   ---- > 2 NH3 (g)

I           4.0       6.0                               0

C          -x           -3x                                2x                               

E          (4.0-x)     (6.0 -3x)                   2x

K = [NH3]2 / [ N2][H2]3   

Lets find equilibrium concentrations of all species.

From the problem condition

[H2]= 1.0 mol

[H2]= (6.0-3x) = 1.0 mol

Therefore

6.0-3x = 1.0 mol

Therefore

6.0-3x = 1.0 mol

3x = 5.0 mol

x = 1.67 mol

Lets assume volume = 1.0 so mole = molarity

[N2] =4.0-x = 4.0-1.67 = 2.33 M

[H2]= 1.0 M

[NH3] = 2x = 2 x 1.67 = 3.33 mol

Lets plug all the values in K expression

K = ( 3.33)2 / ( 2.33) ( 1.0)3

= 4.76

Equilibrium constant for this reaction is = 4.76

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