The four gases NH3, O2, NO, and H2O are mixed in a reaction vessel and allowed t
ID: 903519 • Letter: T
Question
The four gases NH3, O2, NO, and H2O are mixed in a reaction vessel and allowed to reach equilibrium according to the following reaction.
4NH3(g) + 5O2(g) <====> 4NO(g) + 6H2O(g)
(a) Write expressions for Kp and Kc for this reaction. Note that this reaction involves H2O(g), not H2O(l).
(b) The following table lists changes that can be made to this mixture of gases. Considering each change separately, state the effect (increase, decrease, no change) that the change would have on the quantity in the second column. Assume that the temperature and volume remain constant in all cases.
Explanation / Answer
4NH3(g) + 5O2(g) <====> 4NO(g) + 6H2O(g)
Kp = PNO^4 PH2O^6 / PNH3^4 PO2^5
Kc = [NO]^4 [H2O]^6 / [NH3]^4 [O2]^5
b)
+ NO ... then H2O will decrease, since shift goes to reactants
+ NO... then O2 will increase, since shift goes to reactants
- H2O... then NO willl increase, since shift goes to products
- O2... then NH3 will increase since shift goes to reactants
+ NH3, will decrease KC since Kc = 1/[NH3]
- NO, will decrease the NH3 since there is a shift toward reactants
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