3. Two bird species exhibit postzygotic isolation in that half of the hybrids fo

Question

3. Two bird species exhibit postzygotic isolation in that half of the hybrids formed between them are sterile. If Haldane’s rule applies here, then the individuals that are sterile are likely to be (birds have a ZW sex determination system)

female.

male.

young.

old.

a.

female.

b.

male.

c.

young.

d.

old.

Population 1 New mutation Fixation of new mutation A mutation A, B, arises Hybrid Ancestral genotype An sweeps to fixation B, sweeps to B, mutation arises fixation Negative epistasis between Aa and B, Imposes a severe An B2 fitness cost on hybrids Population 2 The figure above illustrates: o ploidy changes resulting in reproductive isolation Haldane's rule. Dobzhans uller incompatibility. reproductive isolation through chromosomal rearrangement

Explanation / Answer

According to chegg rules we can answer only one question in one post.

The answer for the first question is option C. Dobzhansky Muller incompatibility.

An ancestral population splits into two which mutate separately. When both the mutants are crossed, they are mutually incompatible. Since the A-B interaction is not present in the ancestral species, it causes the incompatibility when the two mutants are crossed.

Related Questions

Navigate

• Browse (All)
• Browse 3
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.