1) Please, how do I find the values of k, using the equation ln(1-[V/Vinfinity])

Question

1) Please, how do I find the values of k, using the equation ln(1-[V/Vinfinity])= -kt and the information given in the graph above (see picture). Please, show one example. 2) Please, calculate the value of k from the slope of the line from the graph above (see picture). P.S.: this is related to an org. chemistry I lab-Sn1: A kinetic Reaction. Elapsed Time In(1-[V/Vinf]) 80 133 167 207 245 266 295 322 359 397 447 501 535 580 615 655 735 794 870 923 1004 1009 0.041 -0.126 0.145 -0.189 -0.214 0.276 -0.313 0.352 0.413 0.456 -0.535 -0.609 0.675 0.716 0.79 0.853 0.974 Sn1: A Kinetic Study 0.5 500 1000 1500 2000 Series! Linear (Seri 1.07 | 1.5 1.2 -2 -0.0016x + 0.1672 Elapsed Time, sec 1212 1342 1518 0.001619628 1.77 -2.05 2.37

Explanation / Answer

Solution :-

The sn1 reaction are unimolecular reaction therefore the rate of the reaction depends on the concentration of the alkyl halide only

for the given graph the plot of the ln(V/Vinf) verses time gives the negative slope.

the equation from the graph is y=-0.001600x+0.1672

for the first order reaction the ln concentration vs time shows the negative graph with the straight line

where slope = - k

therefore for the given plot the value of the k is calculated as

slope = -k

-0.0016 = - k

multply both sides by negative sign then we get

0.0016 = k

so the value of the k is 0.0016

k = 0.0016

Related Questions

Navigate

• Browse (All)
• Browse 1
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.