Five moles of TiCl4 are combined with two moles of Ti. a.) How many moles of TiC

Question

Five moles of TiCl4 are combined with two moles of Ti. a.) How many moles of TiCl3 are produced according to the following reaction? b.) Which reactant is the limiting reactant? c.) Which reactant is in excess and how much? 3TiCl4 + Ti -----> 4TiCl3 Five moles of TiCl4 are combined with two moles of Ti. a.) How many moles of TiCl3 are produced according to the following reaction? b.) Which reactant is the limiting reactant? c.) Which reactant is in excess and how much? 3TiCl4 + Ti -----> 4TiCl3 3TiCl4 + Ti -----> 4TiCl3

Explanation / Answer

3TiCl4+Ti-----> 4TiCl3

Stoichiometric ratio of reactants   ( TiCl4: Ti)= 3 :1

actual ratio =5:2 =2.5:1

Ticl4 is the limiting reactant

Ti is the excess reactant

3 moels of TCl4 gives 4 moles of TiCl3

5 moles give 5*4/3= 6.67 moles of TiCl3

3 moles of Ticl4 reacts with 1 mole of Ti

5 moles react with 5/3= 1.66 moles of Ti

excess of Ti= 2-1.66= 0.34 moles

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