Item 2 Part A For the reaction, calculate how many grams of the product form whe

Question

Item 2 Part A For the reaction, calculate how many grams of the product form when 14.4 g of Ca completely reacts Assume that there is more than enough of the other reactant Ca(a) + C12 (g) CaCl2 (a) Submit My Answers Give Up Part B For the reaction, calculate how many grams of the product form when 14.4 g of Br2 completely reacts. Assume that there is more than enough of the other reactant. 2K(s) + Br2(1) 2 KBr(s) Submit My Answers Give Up Part C For the reaction, calculate how many grams of the product form when 14.4 g of O2 completely reacts Assume that there is more than enough of the other reactant 4 Cr(s) + 3 O2 (g) 2 Cr2O3(8)

Explanation / Answer

part A:

Ca + Cl2 = CaCl2

Ca=14.4 g

one mole of CA reacts to form one mole of CaCl2.

moles of CaCl2 = moles of Ca= 14.4/40.01 = 0.36 moles

mass of CaCl2= 0.36x110.98 = 39.95 g

part B:

2K + Br2 = 2KBr

one mole of Br2 gives 2 moles of KBr

moles of Br2= 14.4/159.8 = 0.09 moles

moles of KBr= 2x0.09 = 0.18 moles

mass= 0.18x119 = 21.42 gm

part C:

4 Cr + 3 O2 = 2Cr2O3

3 moles of O2 reacts to give 2 moles of product.

moles of O2= 14.4/32 = 0.45 moles

moles of product= 2/3*0.45 = 0.3 moles

mass = 0.3x152 = 45.6 gm

part D:

2 Sr + O2= 2Sr)

2 moles of Sr gives 2 moles of SrO

moles of Sr=moles of SrO = 14.4/87.62 = 0.164 moles

mass of product = 0.164x103.62 = 16.99 g

Related Questions

Navigate

• Browse (All)
• Browse I
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.