A compound is 27.3 % carbon and 72.7% oxygen . The molar mass is known to be 44.

Question

A compound is 27.3 % carbon and 72.7% oxygen . The molar mass is known to be 44.01 g/mol.
What are the empirical and molecular formulae for this compound ?
A.Empirical and Molecular CO B.Empirical CO2 and Molecular CO C.Empirical CO and Molecular CO2 D. Empirical and Molecular CO2
* Please explain your answer. Much appreciated A compound is 27.3 % carbon and 72.7% oxygen . The molar mass is known to be 44.01 g/mol.
What are the empirical and molecular formulae for this compound ?
A.Empirical and Molecular CO B.Empirical CO2 and Molecular CO C.Empirical CO and Molecular CO2 D. Empirical and Molecular CO2
* Please explain your answer. Much appreciated
What are the empirical and molecular formulae for this compound ?
A.Empirical and Molecular CO B.Empirical CO2 and Molecular CO C.Empirical CO and Molecular CO2 D. Empirical and Molecular CO2
* Please explain your answer. Much appreciated

Explanation / Answer

To get empirical formula from percentage composition first convert % compotition to grams and the calculate the mole ration using the molecular weight of the compounds

for Carbon MW is 12 g/mol

for oxygen MW is 16g/mol

carbon = 27.3/12 = 2.275 mole

oxygen = 72.7/16 = 4.54 mole

Divide the mole number by the smallest if any of the numbers are fractions and then try to find whole numbers for all.

carbon = 2.275/2.275 = 1

oxygen = 4.54/2.275 = 2

So the empirical formula is CO2

So the empirical formula and molecular formula is CO2 answer is D

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