F2(g) + 2Cl2O(g) = 2FClO2(g) + Cl2(g) Expt. # [F2] (M) [Cl2O] (M) Initial rate (
ID: 940016 • Letter: F
Question
F2(g) + 2Cl2O(g) = 2FClO2(g) + Cl2(g)
Expt. # [F2] (M) [Cl2O] (M) Initial rate (M/s)
1 0.05 0.010 5.0 x 10-4
2 0.05 0.040 2.0 x 10-3
3 0.10 0.010 1.0 x 10-3
Calculate the order of the reaction, determine the k, determine t 1/2, how long will it take for the reaction to complete 50% if we double all the reactant concentration.
Explanation / Answer
F2(g) + 2Cl2O(g) = 2FClO2(g) + Cl2(g)
Expt. # [F2] (M) [Cl2O] (M) Initial rate (M/s)
1 0.05 0.010 5.0 x 10-4
2 0.05 0.040 2.0 x 10-3
3 0.10 0.010 1.0 x 10-3
Calculate the order of the reaction, determine the k, determine t 1/2, how long will it take for the reaction to complete 50% if we double all the reactant concentration.
Rate law=
Initial Rate=k [F2]^m [Cl2O]^n m,n=order with respect to F2 and Cl2O respectively
[f2]=initial concentration of F2
[Cl2O]= initial concentration of Cl2Oonstant
K=rate c
5.0*10^-4 =k (0.05)^m (0.010)^n……………….(1)
2.0*10^-3=k (0.05)^m (0.040)^n………………(2)
Divide equation (1) by (2),
5.0*10^-4/2.0*10^-3=(0.010/0.040)^n
2.5*10^-1=(0.25)^n
0.25=(0.25)^n
n=1
Similarly
1.0*10^-3=k (0.10)^m (0.010)^n……………………(3)
Divide equation ,1 by 3
0.5=(0.05/0.10)^m=(0.5)m
m=1
consider any equation say (1) put the value of m,n and compute K,
5.0*10^-4 =k (0.05)^m (0.010)^n
Or, 5.0*10^-4 =k (0.05) (0.010)
K=1 s-1
T1/2=0.693/K=0.693/1 s-1=0.693 s
First order equation
ln Ct/Co=-kt
Ct= concentration of reactant after time t
Co=initial conc of reactant
T=-1/K ln Ct/Co
given
Co’=2Co
Ct’=50% Co=0.5 Co
T=-1/k ln( 0.5 Co/2Co)=-1/K ln 0.25
T=-1/1 S-1 (-1.386)=1.386 s
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