How many moles of oxygen, O, are there in 479.07 g of iron (III) oxide, Fe 2 O 3

Question

How many moles of oxygen, O, are there in 479.07 g of iron (III) oxide, Fe2O3? Molar mass of Fe2O3 is 159.69 g/mol.

9.00 MOL

3.00 MOL

1.00 MOL

0.333 MOL

From the Balanced Chemical Equation: 4 Al + 3O2 --> 2 Al2O3

Apply Stoichiometry to determine the yield (grams) of Al2O3 produced if you start with 108 grams of Al in excess O2 as reactants. Aluminum is the limiting reactant, and oxygen is present in excess. The formula weight of Al2O3 is 101.96 g/mol.

54g

210g

240g

101.96g

239g

Acid HCl reacts with base Mg(OH)2 (milk of magnesia antacid) in an acid-base neutralization in a human stomach. If a patient has secreted 5.0 ml of 2.0M acid and you (a medical professional) wish to administer a pill of pure Mg(OH)2, what pill size (in milligrams) do you need to administer?

600mg

290 mg

10 mg

0.60 mg

Explanation / Answer

How many moles of oxygen, O, are there in 479.07 g of iron (III) oxide, Fe2O3? Molar mass of Fe2O3 is 159.69 g/mol.

apply the next formula

mol = mass/(molar mass)

mol of Fe2O3 = mass/MW = 479.07/159.69 = 3 mol of Fe2O3

note that

1 mol of Fe2O3 contains 3 mol of O3

then

3 mol o must contain triple amount,

that is

3*3 = 9 mol of Oxygen

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