How many moles of oxygen are to fully react with 100 kg of lead sulfide? a. 0.62

Question

How many moles of oxygen are to fully react with 100 kg of lead sulfide? a. 0.6268 moles b. 278.6 moles c. 626.8 moles d. 6268 moles How many kilograms of sulfur dioxide arc made for every 100 kg of lead sulfide that reacts if the yield is 68%? a, 18 kg b, 27 kg c, 39 kg d. 108 kg Based on the phase diagram shown below, which of the following statements are correct? I. Sublimation occurs at a point in the transformation that falls along a straight line from point A to point F. II. C and E represent points where the gas and liquid phases are in equilibrium. III. Delta H_vap can be measured at point B. IV. Molecules at a point D have a greater average kinetic energy than those at point F. V. At point E, all three phases exist. a. II, V b. I III, IV c. I II III d II, IV, V e. I II, IV

Explanation / Answer

Reaction for lead sulfide with oxygen to produce lead sulfide is

PbS + O2 -----> Pb + SO2

1 mole 1 mole 1 mole 1 mole

Molar mass of SO2 = 64 g/mol

Molar mass of PbS = 239.3 g/mol

Molar mass of O2 = 32 g/mol

Given

Mass of SO2 = 200 million tonnes = 200 * 106 tonnes = 200 * 106 * 103 Kg

Mass of PbS required = 200 * 106 * 103 Kg * 239.3 g/mol / 64 g/mol

= 200 * 239.3 / 64 million tonnes of PbS

Answer is d)

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