Find the volume of NaOH used in each experiment. Show all calculations for credi
ID: 947401 • Letter: F
Question
Find the volume of NaOH used in each experiment. Show all calculations for credit. Then, compile results in the table below. Volume NaOH used = Ending volume of NaOH in titrator - Starting volume of NaOH in titrator Find the volume of the excess acid that was neutralized. Volume of 1 M acid neutralized = Volume of 1M HCI - volume of 1M NaOH used Next, convert to the parameters of our experiment (remember, we did it on a much smaller scale!) Volume conversion from 1M to 0.1M = Volume of 1M acid neutralized x 10 Now, convert from mL of acid neutralized to grams of acid neutralized. mL of 0.lM acid = g of 0.1M acid Finally, determine the amount of acid neutralized per gram of antacid to determine the antacids efficacy. acid neutralized per gram of antacid = grams of acid/[(Grams of crushed tablet + weighing paper) - Grams of weighing paper] Mass of antacid tablet mass of crushed tablet used volume of HCL used Starting volume of NaOH in titrator ending volume of NaOH in titrator volume of NaOH used Volume of 1M acid nuetralized Volume conversion for 1M to 0.1 M Mass of 0.1 M acid nuetralized Effectiveness of antacid: acid neutralized per gram of antacidExplanation / Answer
1) Volume of NaOH
Trial 1 :starting volume NaOH - final volume NaOH = 4.4 - 4 = 0.4mL
Trial 2 : starting volume NaOH - final volume NaOH = 4.2 - 3.9 = 0.3mL
2) Volume of excess acid that was neutralized
Volume of acid neutralized = Volume of HCl - Volume of NaOH used
Trial 1 : Volume of acid neutralized = 8 .0 - 0.4 = 7.6 m L
Trial 2: 8.0 - 0.3 = 7.7 mL
3) Volume conversion
Trial 1 : Volume of acid neutralized X 10 = 7.6 X 10 = 76mL
Trial 2: Volume of acid neutralized X 10 = 7.7 X 10 = 77mL
4) Conversion of volume to grams
Trial 1: Grams of acid = 76 grams
Trial 2: Grams of acid = 77 grams
5) Acid neutralized per gram of antacid = grams of acid / [Grams of crushed tablet + weight paper] - [weight of paper]
Trial 1: Acid neutralized per gram of antacid = 76 / (1.2 - 4.5) - 4.5 = 63.33
Trial 2: Acid neutralized per gram of antacid = 77 / (1.3- 4.5) - 4.5 = 59.23
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