a student decides to prepare a standard solution of FeSCN^2+ by dissolving 8.0*1

Question

a student decides to prepare a standard solution of FeSCN^2+ by dissolving 8.0*10^-5 moles of (FeSCN)Cl2 in a liter of water. She thinks she will end up with an 8.0*10^-5 M solution of FeSCN^2 a student decides to prepare a standard solution of FeSCN^2+ by dissolving 8.0*10^-5 moles of (FeSCN)Cl2 in a liter of water. She thinks she will end up with an 8.0*10^-5 M solution of FeSCN^2 a student decides to prepare a standard solution of FeSCN^2+ by dissolving 8.0*10^-5 moles of (FeSCN)Cl2 in a liter of water. She thinks she will end up with an 8.0*10^-5 M solution of FeSCN^2

Explanation / Answer

M = mol/V

V = 1 liter

mol = 8.0*10^-5

M =  8.0*10^-5 / 1 =  8.0*10^-5

that is BEFORE equilibrium

Fe+3 + SCN- <--> FeSCN+2

the constant of formation is not very high, so assume not complete dissociation/formaiton

[ FeSCN+2 ] = not equal to  8.0*10^-5

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