Hello Chegg team I need help with the last one I am stuck... how do I find the a

Question

Hello Chegg team I need help with the last one I am stuck... how do I find the accepted value? I feels like I Am Missing Something Just DONT Know What Please Help

Determining the Ksp of Calcium Hydroxide Exp. # 7 Calcium hydroxide is an ionic solid that is sparingly soluble in water. A saturated, aqueous, solution o Ca(OH)2 is represented in equation form as shown below Ca(OH)2 (s) ="ca2+ (aq) + 2011 (acl) The solubility product expression describes, in mathematical terms, the equilibrium that is established between the solid substance and its dissolved ions in an aqueous system. The equil calcium hydroxide is shown below substance and its dissolved ions in an aqueous system. The equilibrium expression for e constant that illustrates a substance's solubility in water is called the Kp. All compounds, even the highly soluble sodium chloride, have a Kp However, the Kp of a cases where the compound is very slightly soluble and the amount of dissolved ions is not simple to measure Your primary objective in this experiment is to test a saturated solution of calcium hydroxide and use your observations and measure prepared Ca(OH) solution with a standard hydrochloric acid solution. By determining the molar concentration of dissolved hydroxide ions in the saturated Ca(OH) solution, you will have the necessary information to calculate the Kap Figure 1. Experimental setup for determination of the solubility product

Explanation / Answer

Answer – We are given the experimental calculation of the Ksp of the Ca(OH)2 and it is 1.399*10-7. We know the accepted value of Ksp of Ca(OH)2 is the standard one which is already determined and consider as the exact Ksp value. In this one we determine the Ksp value and we need to compare the determined experimental Ksp value of the Ca(OH)2 to the standard values of the Ksp of the Ca(OH)2.

The accepted value of Ksp of Ca(OH)2 is 5.5*10-6 and we found 1.399*10-7, so there is more difference in the value and we didn’t found the value near or approximate due to the experimental error. So there is experimental and accepted values of Ksp is not comparable. There were maybe some errors occurred during the experiment and that given the different result and couldn’t got the experimental value near to accelerated one. There is may be error occurred in the titration and showing some different pH reading. There is another error occurred in the observation. There is error occurred in the solution mixed which are not in the exact amounts and may they gets dilute more or less and that one also show the error in the pH at equivalence point or after the equivalence point. There is maybe error in the calculation of Ksp from the obtaining data.

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