What is the function of the releases factor(RF)? A)It releases the amino acid fr

Question

What is the function of the releases factor(RF)? A)It releases the amino acid from its tRNA to allow the amino acid to form a peptide B) It separates tRNA in the A site from the growing polypeptide. C It supplies a source of energy for termination of translation D) It binds to the stop codon in the A site in place of a tRNA. E) It releases the ribosome from the ER to allow polypeptides in to the cystol Which of the following does not occur in prokaryotic eukaryotic gene expression but does in eukaryotic gene expression? A) RNA polymerase binds to the promoter B) Transcription can begin as soon as translation has begun even a little. C) RNA polymerase requires a primer to elongate the molecule. D) A poly-A tail is added to the 3 end of an mRNA and a cap is added to the 5 end. E) mRNA, tRNA, and rRNA are transcribed. The anticodon of a particular tRNA molecule is A) complementary to the corresponding mRNA codon. B) complementary to the corresponding triplet in rRNA C) the part of tRNA that bonds to a specific amino acid D) catalytic, making the tRNA a ribozyme. E) changeable, depending on the amino acid that attaches to the tRNA. Which component is not directly involved in translation? A) tRNA B. mRNA C) ribosomes D) DNA E) GTP A frameshift mutation could result from A) a base substitution only B) either an insertion or a deletion of a base. a base insertion only D) deletion of three consecutive bases. E) a base deletion only A mutant bacterial cell has a defective aminoacyl synthetase that attaches a lysine to tRNAs with the anticodon AAA instead of the normal phenylalanine. The consequence of this for the cell will be that A) the cell will compensate for the defect by attaching phenylalanine to tRNAs with lysine-specifying anticodons B) none of the options will occur, the cell will recognize the error and destroy the tRNA C) none of the proteins in the cell will contain phenylalanine. D) proteins in the cell will include lysine instead of phenylalanine at amino acid positions specified by the codon UUU E) the ribosome will skip a codon every time a UUU is encountered. In eukaryotic cells, transcription cannot begin until A) the 5 caps are removed from the mRNA. B) several transcription factors have bound to the promoter C) DNA nucleases have isolated the transcription unit. D) the DNA introns are removed from the template. E) the two DNA strands have completely separated and exposed the promoter.

Explanation / Answer

Answer:

6. (D) It binds to the stop codon in the A site in place of a tRNA

Explanation:

The release factor (RF) terminates translation by recognizing the stop codon in the mRNA sequence. It interacts with the stop codon in place of the tRNA and mediate the release of the polypeptide.

7. (D) a poly-A tail is added to the 3' end of an mRNA and a cap is added to the 5' end

Explanation:

The eukaryotic mRNA undergoes post-transcriptional processing of the 5' end of the RNA to form the 5' cap and a poly A tail is added to the 3' end of the transcript. This process is unique to eukaryotes and are not found in prokaryotic transcription.

8. (A) Complementary to the corresponding mRNA codon

Explanation:

The sequence of three bases in the anticodon loop of a tRNA is complementary to the codon in the mRNA. The bases of the anticodon pair up with that of the codon through hydrogen bonds during translation.

9. (D) DNA

Explanation:

DNA is transcribed to synthesize the mRNA through a process called transcription. mRNA is important as the sequence in the mRNA is utilized in the process of translation (protein synthesis). So, mRNA is directly involved in protein synthesis while the involvement of DNA is indirect.

(Since there are multiple questions, the first question have been answered according to the rules of Chegg)

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