Na3PO4 is slowly added to a initial solution [Ca+2] = 1.25 x 10^-4 M, until prec

Question

Na3PO4 is slowly added to a initial solution [Ca+2] = 1.25 x 10^-4 M, until precipitation of Ca3(PO4)2 begins. Given that Ksp for Ca3(PO4)2 = (1.0 x 10^-26).
Find the molar concentration of PO43- (M) at which precipitation of Ca3(PO4)2 will begin. Na3PO4 is slowly added to a initial solution [Ca+2] = 1.25 x 10^-4 M, until precipitation of Ca3(PO4)2 begins. Given that Ksp for Ca3(PO4)2 = (1.0 x 10^-26).
Find the molar concentration of PO43- (M) at which precipitation of Ca3(PO4)2 will begin.
Find the molar concentration of PO43- (M) at which precipitation of Ca3(PO4)2 will begin.

Explanation / Answer

Ca3(PO4)2 ---> 3Ca2+ + 2 PO43-
1.25*10^-4 2s

Ksp = [Ca2+]^3 * [PO43-]^2
1*10^-26 =(1.25*10^-4)^2 * (2s)^2
4*s^2 = 6.4*10^-19
s = 4*10^-10 M
[PO43-] = 2s = 2*4*10^-10 = 8*10^-10
Answer: 8*10^-10 M

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