Data Trial 1 eosu Irial 2 Trial 3 Concentration of standardized HCI solution (md

Question

Data Trial 1 eosu Irial 2 Trial 3 Concentration of standardized HCI solution (md/L) Vol of sat'd Ca(OH)2 with added CaClz soln (mL) Buret reading, initial (mL) Buret reading, final (mL) 1. A 2. 25 wL 3. .118 21 3.56n b.2a 4. &.00 5. Volume of H Calculations 6. Amount of HCI added (mol) 7. Amount of OH- in sat'd solution (mol) 8. [OH-], equilibrium (mol/L) CI added (mL) 9. Molar solubility of Ca(OH)2 with added CaCl2 10. Ave molar solubility of Ca(OH)2 with added CaCl:2 * Calculations for Trial 1.

Explanation / Answer

Ca(OH)2 is di acidic alkali. equation of nutralization

Ca(OH)2 + 2 HCl = CaCl2 + 2 H2O

1 mole of Ca(OH)2 is nutralised by 2 mol HCl.

now

amount of OH - in trial (mol) = trial 1 = 4.86 * 10-4

                                               trial 2 = 4.97 * 10-4

                                               trial 3 = 4.57 * 10-4

mole / L = trial 1:

25 ml solution contaion 4.86 * 10-4 mole OH-

1000 ml (1 liter) contain = .0194 Mole

trial 2 : .0198 Mole

trial 3 : .0182 Mole

molar solubility :

trial 1 :

2 mole of OH- is obtaion from 1 mol of Ca(OH)2

.0194 Mole OH- is obtaion from 0.0097 mole per lit

trial 2 : 0.0099 mole / lit

trial 3 : 0.0091 mole / lit

average value molar of solubility / lit = 0.0095

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