When solutions of silver nitrate and sodium chloride are mixed, silver chloride

Question

When solutions of silver nitrate and sodium chloride are mixed, silver chloride precipitates out of solution according to the equation AgNO_3 (aq) + NaCl (aq) rightarrow AgCl (s) + NaNO_3 (aq) What mass of silver chloride can be produced from 1.58 L of a 0.135 M solution of silver nitrate? Express your answer with the appropriate units. mass of AgCl = The reaction described in Part A required 3.25 L of sodium chloride. What is the concentration of this sodium chloride solution? Express your answer with the appropriate units.

Explanation / Answer

A) 0.135 M means 0.135 moles of AgCl in 1L of solution. therefore no. of moles in 1.58 L = 1.58 X 0.135 = 0.2133 moles. Molar mass of AgCl = 143.32 g. therefore mass of AgCl = 0.2133 X 143.32 = 30.57 g

B) to prepare 0.2133 moles of AgCl we will need 0.2133 moles of NaCl. Conc. = moles/L = 0.2133/3.25 = 0.656 M

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