The above galvanic cell involves a half-cell constructed from an unspecified met
ID: 977232 • Letter: T
Question
The above galvanic cell involves a half-cell constructed from an unspecified metal, M. The salt bridge is packed with NaCl. The cell is not necessarily shown in standard convention (i.e. the electron flow is not necessarily from left to right.)
a) As the cell operates, the mass of the M electrode decreases. Based on this observation, what can you say about:
(i) The electron flow through the wire connecting the half cells? Electrons flow from: (left to right or right to left)
Explain your reasoning:
(ii) The flow of Na+ through the salt bridge? Na+ ions flow from: (left to right or right to left)
Explain your reasoning:
c) If the concentrations of M+3 in the half-cell on the left is decreased to 0.1 M and the concentration of the Co+2 solution in the half-cell on the right is increased to 2.0 M, what happens to the absolute value of the reading on the voltmeter: The magnitude (absolute value) of the reading on the volt meter: (increases or decreases (circle one)) by ____________ V.
Show your work:
d) The cell can be used to run an electric motor. Consider the above cell, in which both solutions are at 1.0M, and a cell in which both solutions are 0.5 M.
Which cell would have a higher cell potential? (1.0 M cell) (0.5 M cell) (they would be the same) (circle one)
Explain:
Which cell would run the motor longer? (1.0 M cell) (0.5 M cell) (they would be the same) (circle one)
Explain:
Explanation / Answer
1) since the mass of M electrode decreases ...this reaction is taking place ...M ----> M3+ + 3e- ..so since left side is provoding electrons the righ tsie must accepting it ...flow is from left to right.
2) we now know that oxidation is taking place on electrode with metal M hence it's annode ...and salt bridge helps in electron transport ..so the electrons will flow to cathode. ie from left to right.
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