The following concentrations were determined in the five trials: 6.049 g/L, 6.07

Question

The following concentrations were determined in the five trials: 6.049 g/L, 6.073 g/L, 6.081 g/L, 6.002 g/L, and 6.034 g/L. Use these values to answer the next six questions. Except where noted, report values with units.

What is the mean value for this data set? 6.048 g/L

What is the standard deviation of this data? 0.032 g/L

What is the variance of this data?

What is the RSD for this data?

Based upon this data, at the 95% confidence level the true concentration (population mean) is expected to be between what two values?

Maximum concentration?

Minimum concentration?

Explanation / Answer

1) Mean value = 6,048 g/L

2) standard deviation = 0,032 g/L

3) variance = 0,001 g2/L2

4) we choose a z value of 1.96 as this value corresponds to the area under the standard normal distribution that encompasses 95% of all values:

P95% = 6,020 g/L and 6,076 g/L

Maximum concentration = 6,081 g/L

Minimum concentration = 6,002 g/L

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