The classical Ramachandran diagram is calculated without considering hydrogen bo

Question

The classical Ramachandran diagram is calculated without considering hydrogen bonding energy (only the van der Waals energy is used). Nevertheless, note that the regions of the Ramachandran diagram that are “allowed” correspond to conformations of the chain (secondary structure) that lead to nice hydrogen bonding patterns between N-H and C=O groups of the backbone. Circle TRUE or FALSE for each statement.

(i) The peptide backbone is very flexible, and has so many hydrogen bonding groups, that any conformation will result in good hydrogen bonding geometry TRUE / FALSE

(ii) The ability of secondary structural elements to form hydrogen bonds reflects the fact that hydrogen bond formation between the N-H and C=O groups drives protein folding TRUE / FALSE

(iii) The attraction between the peptide N-H and C=O groups is so strong that the chain always adopts conformations in which they are brought together TRUE / FALSE

(iv) When a protein molecule folds, polar groups that are removed from water need to make compensating hydrogen bonds within the folded structure. The Ramachandran diagram reflects the fact that the peptide chain can fold in water without losing significant hydrogen bonding energy TRUE / FALSE

Explanation / Answer

1) False , only some confirmations will result in good hydrogen bonding

( ii) True , folding of protein is driven by Hydrogen bonding ability

( iii) True , hydrogen bonding is main intramolecular force

( iv) True ,

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