A typical gold bar has dimensions of being 82mm long, 45mm wide and 16mm deep. T

Question

A typical gold bar has dimensions of being 82mm long, 45mm wide and 16mm deep. The current price for gold is $1,368 per ounce (mass). a. What is the total surface area, in square inches, of the gold bar? b. Determine how many mL of gold were used to make the gold bar. c. If the density of gold is 19.3 g/cm3, what would be the cost of this gold bar? A typical gold bar has dimensions of being 82mm long, 45mm wide and 16mm deep. The current price for gold is $1,368 per ounce (mass). a. What is the total surface area, in square inches, of the gold bar? b. Determine how many mL of gold were used to make the gold bar. c. If the density of gold is 19.3 g/cm3, what would be the cost of this gold bar? a. What is the total surface area, in square inches, of the gold bar? b. Determine how many mL of gold were used to make the gold bar. c. If the density of gold is 19.3 g/cm3, what would be the cost of this gold bar?

Explanation / Answer

a)

area

A = L*W = 82mm*45 mm = 3690 mm^2

since 645.16 mm^2= 1 in ^2 then

3690 /645.16 = 5.719 in^2

b)

ml of gold

V = A*d = 3690 *16 = (59040 mm^3)(1 cm/10mm)^3 = 59040 /(10^3) = 59.04 cm^3

since 1 cm^3 = 1 ml then

V = 59.04 ml

c)

D = 19.3 g/cm3

then

mass = D*V = 19.3*59.04 = 1139.472 g of gold

since 1 oz = 28.3495 g

then

1139.472 / 28.3495 = 40.19 oz of gold

we pay 1368$ per oz so

40.19*1368 = $54,979.92

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