TIONS ee standard potential table in your textbook, page 891, when answering the
ID: 986261 • Letter: T
Question
TIONS ee standard potential table in your textbook, page 891, when answering the following complete the following table. If the species listed can be used as an oxidizing agent, write Y Oidizing Agent column and write its reduction half-reaction in the next agent, write YES in the axdizing agent write NO in the oxidizing Agent column and leave the next column blank If the species li can be used as a reducing reaction in the last column. If it cannot be used as a reducing agent, write NO in the Reducing Agent column and leave the last column blank next column blank. If the species listed nt, write YES in the Reducing Agent column and write its oxidation half- Highi side oP labl Oxidizing Reduction Half-Reaction Reducing Agent? Oxidation Half-Reaction Agent? Mno. Br HCI Indicate whether each of the following statements is true, T, or false, F. In each case, briefly explain your response 2. a. Chromium metal can dissolve in dilute HCI b. Iron metal will reduce Fe to Fe c. Silver metal will dissolve in nitric acid, liberating H2 gas d. Oxygen in moist air can oxidize Fe to Fe e. Mercury metal will dissolve in HNOs, but not in HCI f. Tin metal will reduce Co, but not Sn b. IronExplanation / Answer
K = Reducing
K usually forms K+, because it's a cation. It donates electron to other element, so it's reducing.
K+ e- -à K+
Fe2+: Oxidizing
except it takes 2 electrons away,
Fe2+ + 2e --- > Fe
MnO4-
The Mn is +7 can be converted to Mn+2 or Mn+4 in MnO2, so it is an oxidizing agent
MnO4- + 3e - --à MnO2
Br2= oxidizing agent
If Br2 forms a compound with another element, it will usually end up taking one electron from the other element to create an octet
Br2 + 2e- ---- > 2Br-
S goes from oxidation number -2 to 0 ( this is an oxidation ) so H2S is the reducing agent
H2S + 2e - --- > 2H+ +S
HCl
HCl is an oxidizing compound, because
HCl --- > H+ Cl-
2H+ + 2e- --> H2
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