What are the hybridizations of the carbon atoms labeled C_1 and C_2, respectivel

Question

What are the hybridizations of the carbon atoms labeled C_1 and C_2, respectively, in the amino acid, glycine? C_1 C_2 sp^2 sp^2 sp^2 sp^2 sp^3 sp^3 sp^3 sp^2 sp sp For a given arrangement of ions, lattice energy decreases as ionic radius and as ionic charge increases, decreases increases, increases decreases, increases decreases, decreases this cannot be predicted. For the next two questions consider the following Lewis Structure The nitrogen/nitrogen double bond includes a sigma bond made from the overlap of hybridized sp orbitals from both nitrogens hybridized sp^2 orbitals from both nitrogens hybridized sp^3 orbitals from both nitrogens atomic s orbitals from both nitrogens atomic p orbitals from both nitrogens The nitrogen/nitrogen double bond includes a pi bond made from the overlap of... hybridized sp orbitals from both nitrogens hybridized sp^2 orbitals from both nitrogens hybridized sp^3 orbitals from both nitrogens atomic s orbitals from both nitrogens atomic p orbitals from both nitrogens Consider the polyatomic ions NO_2^+, NO_2^-, and NO_3^-. Which has the largest bond order, which the smallest? NO_2^+ has the highest bond order and NO_3^- has the lowest bond order. NO_2^- has the highest bond order and NO_2^+ has the lowest bond order. NO_3^- has the highest bond order and NO_2^- has the lowest bond order. NO_2^+ has the highest bond order and NO_2^- has the lowest bond order. NO_2^- has the highest bond order and NO_3^- has the lowest bond order. A Lewis Structure of which of the following polyatomic ions has a central atom that can be drawn with expanded octet? CO_3^2- NH_4^+ NO_2^- NO_3^- CIO_4^-

Explanation / Answer

Question 12.

When Carbon it's bonded with 4 single bonds, it means that it has the simpliest hybridation, which is sp3, cause it's using only sigma bonds and when one of two of it's bond is with a double bond, it's using a sigma bond but also a pi bond, so it's using a sp2 hybridation form

Question 14 and 15.

The sigma bond as I previously state in question 12 is formed in the hybridation of sp3 form, so the correct answer in here is option C, sp2 and sp are used for double and triple bond. In the same way, in order to form the double bond with the N, the pi bond is formed with the hibridized form of sp2, so correct option here is b.

The other questions, post them in another post.

Hope this helps

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